Using Formulas To Solve Problems

Using Formulas To Solve Problems-79
The total work is 24 units, which Rita can finish the work of her own in 24/1 = 24 hours. In 10 days B will do 10 × 1/40 = 1/4th of the work.Remaining work 1 - ¼ = ¾ (Which A and B have done together). Their one-day’s work is 1/60 1/40 = (2 3)/120 = 5/120 = 1/24. They would have done three-fourth of the work in 24 × 3/4 = 18 days. Or As discussed earlier in time work questions, time and work tricks like the unit approach can also be applied.The formula for the area of a triangle is A is equal to 1/2 b times h, where A is equal to area, b is equal to length of the base, and h is equal to the length of the height. That is the height of the triangle-- let me do that at a lower case h because that's how we wrote it in the formula.

The total work is 24 units, which Rita can finish the work of her own in 24/1 = 24 hours. In 10 days B will do 10 × 1/40 = 1/4th of the work.Remaining work 1 - ¼ = ¾ (Which A and B have done together). Their one-day’s work is 1/60 1/40 = (2 3)/120 = 5/120 = 1/24. They would have done three-fourth of the work in 24 × 3/4 = 18 days. Or As discussed earlier in time work questions, time and work tricks like the unit approach can also be applied.The formula for the area of a triangle is A is equal to 1/2 b times h, where A is equal to area, b is equal to length of the base, and h is equal to the length of the height. That is the height of the triangle-- let me do that at a lower case h because that's how we wrote it in the formula.

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Example 1 – Walter and Helen are asked to paint a house.

Walter can paint the house by himself in 12 hours and Helen can paint the house by herself in 16 hours.

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Or You can take the total work to be equal to 120 units (the LCM of 24, 20 & 8).

That implies A does 120/24 = 5 units a day, B does 120/20 = 6 units a day. Now if C does 4 units a day, he can finish the work in 120/4 = 30 days. If we add all this it will give us the work of 2A, 2B and 2C in 1 day i.e.

And we're almost there, we have a b multiplying by an h. So we get h-- and I'm just swapping the sides here.

If we want to just isolate the h, we could divide both sides of this equation by b.

This can be done by first multiplying the entire problem by the common denominator and then solving the resulting equation. Click Here for Practice Problems Example 4 – One roofer can put a new roof on a house three times faster than another. How long would it take the faster roofer working alone?

This can be done by first multiplying the entire problem by the common denominator and then solving the resulting equation. Click Here for Practice Problems Example 5 – Triplets, Justin, Jason, and Jacob are working on a school project.

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